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Archive for August 26th, 2015

for %n = 1 to 100 step 1 do: windows – Batch script loop – Stack Overflow

Posted by jpluimers on 2015/08/26

Thanks Jon for answering this:

for /l is your friend:

for /l %x in (1, 1, 100) do echo %x

Starts at 1, steps by one, and finishes at 100.

Use two %s if it’s in a batch file

for /l %%x in (1, 1, 100) do echo %%x


via: windows – Batch script loop – Stack Overflow.

Posted in Batch-Files, Development, Scripting, Software Development | Leave a Comment »

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